-^(1-7n)+4=10+9(n-5)

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Solution for -^(1-7n)+4=10+9(n-5) equation: 



-^(1-7n)+4=10+9(n-5)

We move all terms to the left:

-^(1-7n)+4-(10+9(n-5))=0

We add all the numbers together, and all the variables

-^(-7n+1)-(10+9(n-5))+4=0



We calculate terms in parentheses: -(10+9(n-5)), so:

10+9(n-5)

determiningTheFunctionDomain
9(n-5)+10

We multiply parentheses

9n-45+10

We add all the numbers together, and all the variables

9n-35

Back to the equation:

-(9n-35)



We get rid of parentheses

-^(-7n+1)-9n+35+4=0

We add all the numbers together, and all the variables

-9n-^(-7n+1)+39=0

We move all terms containing n to the left, all other terms to the right

-9n-^(-7n+1)=-39

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